How many intercepts can a line have?

2 Answers
Apr 11, 2018

see below

Explanation:

some lines may have no intercepts with the x-x or with the y-y axis.

this includes lines such as y = 1/xy=1x.
graph{1/x [-5.23, 5.23, -2.615, 2.616]}

there is no point on the graph where x = 0x=0, since 1/010 is undefined. this means that there cannot be a y-yintercept for this graph.

though the y-yvalue does tend to 00 as xx goes to the far right or far left (to -oo or oo), yy never reaches 00, since there is no number that you can divide 11 by to get 00.

since there is no point on the graph where y = 0y=0, there is no x-xintercept for this graph.

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graphs where an x-x or y-y value is constant will have one intercept.

if the x-x value is constant, and xx is not 00, then there will only be a x-x intercept (where y = 0y=0, and xx is the constant).

if the y-y value is constant, and yy is not 00, then there will only be a y-y intercept (where x = 0x=0, and yy is the constant).

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all linear graphs, where y = mx + cy=mx+c and m != 0m0, either have one intercept with each axis or have one intercept with the origin where both axes cross.

graph{x + 3 [-10, 10, -5, 5]}
the graph y = x + 3y=x+3 has its x-xintercept at (-3,0)(3,0) and its y-yintercept at (0,3)(0,3).

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all parabolas, where xx has 22 real roots, have 22 x-xintercepts. they may also have a y-yintercept.

graph{x^2 - 2 [-10, 10, -5, 5]}

the roots of the graph are the points where yy is 00, and the solutions for xx are the x-xcoordinates at these points.

the graph shown is y = x^2 - 2y=x22; its roots are (-sqrt2,0)(2,0) and (sqrt2,0)(2,0)

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there are examples of graphs with many more x-x and y-y intercepts.

the last example in this answer will be some with infinite xx-intercepts.

the graphs of y = sin xy=sinx, y = cos xy=cosx and y = tan xy=tanx all repeat periodically. this means that they meet the x-xaxis at set intervals, and at an infinite number of points.

graph{sin x [-10, 10, -5, 5]}

the graph of sin xx, for example, has an x-xintercept at every 180^@180 on the x-xaxis.

Apr 11, 2018

It is possible for a line to have an infinite number of intercepts with the xx or yy-axis.

Explanation:

It is possible for a line to have an infinite number of intercepts with the xx or yy-axis.

The line x=0x=0 has an infinite number of intercepts with the yy-axis.

The line y=0y=0 has an infinite number of intercepts with the xx-axis.

Any line of the format

y=mx+by=mx+b

where mne0m0 has exactly one yy-intercept and one xx-intercept. If b=0b=0, then both the xx and yy-intercepts are at the origin (0,0)(0,0).