How do you find the inverse of $f(x)=-(1/3)^x$ ?

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Answer 1 · 2016-03-21T14:48:51

x = $-log(-f(x))/log 3$

Here f(x) < 0 for all x.

$f(x) =-3^(-x)$ .

So, $log (-f(x))=-x log 3$ .
x = $-log(-f(x))/log 3$

How do you find the inverse of f(x)=-(1/3)^xf(x)=-(1/3)^x?