How do you find the inverse of $f (x) = \frac{2}{x + 1}$ $f(x)= 2/(x+1)$ and is it a function?

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How do you find the inverse of $f (x) = \frac{2}{x + 1}$ $f(x)= 2/(x+1)$ and is it a function?

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Answer 1 · 2017-04-06T04:46:01

$x = \frac{2}{y} - 1$ $x = 2/y -1$

Explanation:

$y = \frac{2}{x + 1}$ $y=2/(x+1)$
cross multiply
$x + 1 = \frac{2}{y}$ $x+1=2/y$
$x = \frac{2}{y} - 1$ $x = 2/y -1$
This is not a function as at y = 0 it is not defined but the original function is also not a function as at x = -1 it is not defined

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How do you find the inverse of $f (x) = \frac{2}{x + 1}$ $f(x)= 2/(x+1)$ and is it a function?

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Explanation:

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How do you find the inverse of $f (x) = \frac{2}{x + 1}$ $f(x)= 2/(x+1)$ and is it a function?