How do you find the inverse of $f (x) = 3 ln (x - 2)$ $f(x) = 3 ln (x-2)$ and is it a function?

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Answer 1 · 2016-05-08T15:01:02

$x > 3$ $x > 3$ .
Let y = f(x) Then, the inverse function is $x = 2 + e^{\frac{y}{3}}$ $x = 2 + e^(y/3)$

Let $y = f (x) = 3 ln (x - 2)$ $y = f(x) = 3 ln(x-2)$ . Here, x > 2..

$ln (x - 2) = \frac{y}{3}$ $ln (x-2)=y/3$ .

Inversely, $x - 2 = e^{\frac{y}{3}}$ $x-2=e^(y/3)$ .

So, $x = 2 + e^{\frac{y}{3}}$ $x = 2 + e^(y/3)$

How do you find the inverse of f(x)=3ln(x−2)f(x) = 3 ln (x-2) and is it a function?