How do you find the inverse of $f(x) =ln(4x-1)$ ?

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Answer 1 · 2018-04-27T12:35:09

$f^(-1)(x)=(e^x+1)/4$

As $f(x)=y=ln(4x-1)$

$4x-1=e^y$

or $x=(e^y+1)/4$

Hence $f^(-1)(x)=(e^x+1)/4$

How do you find the inverse of f(x) =ln(4x-1)f(x) =ln(4x-1)?