How do you find the inverse of $f (x) = \frac{x - 1}{5}$ $f(x)=(x-1)/5$ ?

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Answer 1 · 2017-01-06T06:21:38

The answer is $= 5 x + 1$ $=5x+1$

Let $y = \frac{x - 1}{5}$ $y=(x-1)/5$

$5 y = x - 1$ $5y=x-1$

$x = 5 y + 1$ $x=5y+1$

Therefore,

$f^{- 1} (x) = 5 x + 1$ $f^-1(x)=5x+1$

Verification

$f (f^{- 1} (x)) = f (5 x + 1) = \frac{5 x + 1 - 1}{5}$ $f(f^-1(x))=f(5x+1)=(5x+1-1)/5$

$= x$ $=x$

How do you find the inverse of f(x)=(x-1)/5f(x)=x−15f(x)=(x-1)/5?