How do you find the inverse of f(x)=x^2+2x-5f(x)=x2+2x5 and is it a function?

1 Answer
Jul 20, 2016

f^1f1 does not exist.

Explanation:

Let us recall that, the inverse of a given function exists, if and only if , the given function is a bijection , i.e., the given function is a 1 - 1 ( one-to-one , or, injection ) and onto ( or, surjection ).

Observe that, for the given function ff, it is not injective, because,

f(x)=x^2+2x-5=x(x+2)-5f(x)=x2+2x5=x(x+2)5, so that, f(0)=-5=f(-2)f(0)=5=f(2), meaning that ff is an m-1m1 or, a many-to-onemanyo and not a 1-111 function.

Hence, f^1f1 does not exist.