How do you find the inverse of $f (x) = x^{2} + 9$ $f(x) = x^2 + 9$ ?

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How do you find the inverse of $f (x) = x^{2} + 9$ $f(x) = x^2 + 9$ ?

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Answer 1 · 2015-12-26T23:57:24

$\times f^{- 1} (x) = \sqrt{x - 9}$ $color(white)xxf^-1(x)=sqrt(x-9)$

Explanation:

$\times f (x) = x^{2} + 9$ $color(white)xxf(x)=x^2+9$

$\times y = x^{2} + 9$ $color(white)xxy=x^2+9$
$\Rightarrow y - 9 = x^{2} + 9 - 9$ $=>ycolor(red)(-9)=x^2+9color(red)(-9)$
$\Rightarrow \sqrt{x^{2}} = \sqrt{y - 9}$ $=>sqrt(x^2)=sqrt(y-9)$

$\Rightarrow f^{- 1} (x) = \sqrt{x - 9}$ $=>f^-1(x)=sqrt(x-9)$

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How do you find the inverse of $f (x) = x^{2} + 9$ $f(x) = x^2 + 9$ ?

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Explanation:

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How do you find the inverse of f(x)=x2+9 f(x) = x^2 + 9?

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Impact of this question

How do you find the inverse of $f (x) = x^{2} + 9$ $f(x) = x^2 + 9$ ?