Question

How do you find the inverse of `f(x)=x^2` and graph both f and `f^-1`?

Answer 1

`f^-1 = sqrt x`

Explanation:

Let `f(x)=y=x^2`. For finding`f^-1`, interchange x and y and solve for y. Thus,

`x= y^2 -> y = sqrtx`

`f^-1` is thus `sqrt x`