How do you find the inverse of $g(x)=(x-5) / 2$ ?

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Answer 1 · 2016-01-08T19:04:37

$f^-1(x) = 2x + 5$

if you rewrite the equation as $y = (x - 5 )/2$

then to find the inverse function ie. what is x in term of y you just have to change the subject to x.

$y = (x - 5 )/2 rArr x - 5 = 2y$

and so x = 2y + 5

finally change the y back to x so that the function is a function of x.

$rArr f^-1(x) = 2x + 5$

How do you find the inverse of g(x)=(x-5) / 2g(x)=(x-5) / 2?