How do you find the inverse of $ln(8x + 1)$ and is it a function?

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Answer 1 · 2016-04-17T07:26:12

Inverse of $ln (8x+1)$ is $(e^y-1)/8$

Let $y=ln(8x+1)$ which gives us

$e^y=8x+1$ or

$8x=e^y-1$ or $x=(e^y-1)/8$

Henve inverse of $ln(8x+1)$ is $(e^y-1)/8$

How do you find the inverse of ln(8x + 1) ln(8x + 1) and is it a function?