How do you find the inverse of $y = 1 - 6 x^{3} - 3$ $y=1-6x^3-3$ and is it a function?

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Answer 1 · 2016-04-20T00:54:56

The inverse of a function can be found by switching the x and y values inside a function.

$x = - 2 - 6 y^{3}$ $x = -2 - 6y^3$

$x + 2 = - 6 y^{3}$ $x + 2 = -6y^3$

$- \frac{1}{6} x - \frac{1}{3} = y^{3}$ $-1/6x - 1/3 = y^3$

$\sqrt[3]{- \frac{1}{6} x - \frac{1}{3}} = y$ $root(3)(-1/6x - 1/3) = y$

So, $f^{- 1} (x) = \sqrt[3]{- \frac{1}{6} x - \frac{1}{3}}$ $f^-1(x) = root(3)(-1/6x - 1/3)$

Hopefully this helps!

How do you find the inverse of y=1-6x^3-3y=1−6x3−3y=1-6x^3-3 and is it a function?