How do you find the inverse of y =1/logx?

1 Answer
Dec 13, 2015

color(white)(xx)f^-1(x)=root(x)10

Explanation:

color(white)(xxx)y=1/logx

=>color(red)(logx xx1/yxx)y=color(red)(logx xx1/yxx)1/logx
=>logx=1/y
=>x=10^(1/y)color(white)(xxxxxxxxxxxx) (logarithm definition)

=>f^-1(x)=root(x)10