How do you find the inverse of $y = 3^x$ ?

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Answer 1 · 2015-11-30T14:38:18

$f^-1=log_3x$

$y=3^x$
$=>log_3y=log_3(3^x)$ (logarithms of both side are equal)
$=>x=log_3y$
$=>f^-1=log_3x$

How do you find the inverse of y = 3^xy = 3^x?