How do you find the inverse of $y=(4x+2)/(x-7)$ ?

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Answer 1 · 2015-12-01T13:43:26

$x=(7y+2)/(y-4)$

You must isolate $x$ in terms of $y$ : multiply both sides by $x-7$ :

$(x-7)y = 4x+2$

$xy-7y = 4x+2$

$xy-4x=7y+2$

$x(y-4)=7y+2$

$x=(7y+2)/(y-4)$

How do you find the inverse of y=(4x+2)/(x-7)y=(4x+2)/(x-7)?