How do you find the inverse of $y=log_2 2x$ and is it a function?

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Answer 1 · 2016-10-21T18:46:46

$y = log_2(2x)$

We obtain the inverse by switching the x and y values within the function.

$x= log_2(2y)$

$2^x = 2y$

$y= 1/2(2^x)$

$f^-1(x) = 1/2(2^x)$

Hopefully this helps!

How do you find the inverse of y=log_2 2xy=log_2 2x and is it a function?