How do you find the inverse of $y = - {log}_{5} (- x)$ $y=-log_5(-x)$ ?

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Answer 1 · 2016-02-13T23:38:53

$x = - 5^{- y}$ $x=-5^(-y)$

$y = - {log}_{5} (- x)$ $y=-log_5(-x)$ , with x<0

$- y = {log}_{5} (- x)$ $-y=log_5(-x)$ , with x<0

if we have $a = {log}_{b} (c)$ $a =log_b(c)$ we will have $b^{a} = c$ $b^a=c$ , if c>0

$5^{- y} = - x$ $5^(-y)=-x$

$x=-5^(-y)= -1/(5^y)<0 AA y in RR$

How do you find the inverse of y=-log_5(-x) y=−log5(−x)y=-log_5(-x) ?