How do you find the inverse of $y=log_7 49^x$ ?

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Answer 1 · 2016-02-29T06:36:52

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$log_a b^x = xlog_a b$
$y = log_7 49^x$
Using the fact that $7^2=49$
$= log_7 7^(2x)$
$y=2xlog_7 7$
$y = 2x$

How do you find the inverse of y=log_7 49^xy=log_7 49^x?