How do you find the inverse of $y = log (x + 4)$ $y=log(x+4)$ ?

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Answer 1 · 2015-11-23T02:51:34

$y = 10^{x} - 4$ $y=10^x-4$

Flip the $x$ $x$ and $y$ $y$ .

$x = log (y + 4)$ $x=log(y+4)$

We want to solve for $y$ $y$ .
Remember that $log (y + 4)$ $log(y+4)$ can also be written as ${log}_{10} (y + 4)$ $log_10(y+4)$ .

$x = {log}_{10} (y + 4)$ $x=log_10(y+4)$

$10^{x} = 10^{{log}_{10} (y + 4)}$ $10^x=10^(log_10(y+4))$

$10^{x} = y + 4$ $10^x=y+4$

$y = 10^{x} - 4$ $y=10^x-4$

How do you find the inverse of y=log(x+4)y=log(x+4)y=log(x+4)?