Question

How do you find the maximum and minimum of `y=-2(x+1)^2+6`?

Answer 1

Find the vertex.

Explanation:

Finding the maximum or minimum for a quadratic equation like this one is code for finding the vertex.

If `y=a(x-h)^2+k` then vertex is `(h,k)`

In this case is `-h=1` and `k=6`
So vertex is `(-1,6)`

Also, whenever a is negative in this format of equation that means you have a downward-opening parabola. Therefore the vertex is a maximum. So the maximum occurs at `(-1,6)`. There is no minimum because the parabola continues down forever.