How do you find the midpoint of (2,6) (-1,1)?

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How do you find the midpoint of (2,6) (-1,1)?

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Answer 1 · 2018-06-08T17:26:41

$(\frac{1}{2}, \frac{7}{2})$ $(1/2,7/2)$

Explanation:

$given endpoints (x_{1}, y_{1}) and (x_{2}, y_{2}) then$ $"given endpoints "(x_1,y_1)" and "(x_2,y_2)" then"$

$the midpoint of the points is$ $"the midpoint of the points is"$

$∙ x [\frac{1}{2} (x_{1} + x_{2}), \frac{1}{2} (y_{1} + y_{2})]$ $•color(white)(x)[1/2(x_1+x_2),1/2(y_1+y_2)]$

$here (x_{1}, y_{1}) = (2, 6) and (x_{2}, y_{2}) = (- 1, 1)$ $"here "(x_1,y_1)=(2,6)" and "(x_2,y_2)=(-1,1)$

$midpoint = [\frac{1}{2} (2 - 1), \frac{1}{2} (6 + 1)]$ $"midpoint "=[1/2(2-1),1/2(6+1)]$

$\times \times \times \times = (\frac{1}{2}, \frac{7}{2})$ $color(white)(xxxxxxxx)=(1/2,7/2)$

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How do you find the midpoint of (2,6) (-1,1)?

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