How do you find the midpoint of (-3,5) and (4,-2)?

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Answer 1 · 2016-03-19T22:44:47

$(1/2,3/2)$

Call the midpoint $(x,y)$

$x=(-3+4)/2=1/2$

$y=(5+(-2))/2=3/2$

Therefore midpoint is $(1/2,3/2)$

Answer 2 · 2016-03-19T22:53:45

Just another way of writing the same thing:
$P_("mid")->(x,y)=(1/2,3/2)$

Mid point is $1/2$ way between given points

Using mean values

Let $P_1 ->(x_1,y_1)->(-3,5)$
Let $P_2->(x_2,y_2)->(4,-2)$

So $" "x_("mid") -> (x_1+x_2)/2 = (-3+4)/2 = +1/2$

So $" "y_("mid") -> (y_1+y_2)/2 = (5-2)/2 = +3/2$

$P_("mid")->(x,y)=(1/2,3/2)$