How do you find the midpoint of (5, 2) and (8,-7)?

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How do you find the midpoint of (5, 2) and (8,-7)?

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Answer 1 · 2016-02-13T22:02:07

$(\frac{13}{2}, - \frac{5}{2})$ $(13/2 , -5/2 )$

Explanation:

use the mid-point formula

$[\frac{1}{2} (x_{1} + x_{2}), \frac{1}{2} (y_{1} + y_{2})]$ $[1/2(x_1 + x_2) , 1/2(y_1 + y_2)]$

here let $(x_{1}, y_{1}) = (5, 2) and (x_{2}, y_{2}) = (8, - 7)$ $(x_1 , y_1) = (5 , 2 )color(black)(" and (x_2 , y_2) = (8 , -7)$
now substitute these values into the formula.

$= [\frac{1}{2} (5 + 8), \frac{1}{2} (2 - 7)] = (\frac{13}{2}, - \frac{5}{2})$ $= [1/2(5+8) , 1/2(2 - 7 )] = (13/2 , -5/2)$

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How do you find the midpoint of (5, 2) and (8,-7)?

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