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How do you find the midpoint of (a,b) and (3a,c)?

1 Answer

Jun 16, 2017

$(2 a, \frac{1}{2} (b + c))$ $(2a,1/2(b+c))$

Explanation:

$the coordinates of the midpoint are the average of the$ $"the coordinates of the midpoint are the average of the "$
$coordinates of the endpoints$ $"coordinates of the endpoints"$

$\Rightarrow [\frac{1}{2} (a + 3 a), \frac{1}{2} (b + c)]$ $rArr[1/2(a+3a),1/2(b+c)]$

$= (2 a, \frac{1}{2} (b + c))$ $=(2a,1/2(b+c))$

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