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How do you find the midpoint of the line segment joining (10,12) (6,9)?

1 Answer

Aug 1, 2016

$(8, \frac{21}{2})$ $(8,21/2)$

Explanation:

The x-coordinate of the midpoint is the average of the x-coordinates and the y-coordinate of the midpoint is the average of the y-coordinates.

$\Rightarrow x_{M} = \frac{1}{2} (10 + 6) = 8$ $rArrx_M=1/2(10+6)=8$

and $y_{M} = \frac{1}{2} (12 + 9) = \frac{21}{2}$ $y_M=1/2(12+9)=21/2$

$\Rightarrow midpoint at (8, \frac{21}{2})$ $rArr" midpoint at " (8,21/2)$

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