How do you find the midpoint of the line segment joining A(-1,3) and B(-5,9)?

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How do you find the midpoint of the line segment joining A(-1,3) and B(-5,9)?

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Answer 1 · 2016-07-27T11:24:34

$(- 3, 6)$ $(-3,6)$

Explanation:

It is the mean values

$\Rightarrow P_{mid} \to (x, y) = (\frac{- 1 - 5}{2}, \frac{3 + 9}{2}) = (- 3, 6)$ $=>P_("mid")->(x,y)=( (-1-5)/2,(3+9)/2) = (-3,6)$

Answer 2 · 2016-07-27T11:27:47

$(- 3, 6)$ $(-3,6)$ .

Explanation:

The midpoint $M (x, y)$ $M(x,y)$ of the segment joining pts. $(x_{1}, y_{1}) and (x_{2}, y_{2})$ $(x_1,y_1) and (x_2,y_2)$ is given by $x = \frac{x_{1} + x_{2}}{2}, y = \frac{y_{1} + y_{2}}{2}$ $x=(x_1+x_2)/2, y=(y_1+y_2)/2$ .

Hence, the reqd. mid-pt. is $(- 3, 6)$ $(-3,6)$ .

Answer 3 · 2016-07-27T11:27:55

$M (- 3, 6)$ $M(-3, 6)$

Explanation:

In easy English this is:

"Average of the x-values and the average of the y-values."

The formula is $M (\frac{x_{1} + x_{2}}{2}; \frac{y_{1} + y_{2}}{2})$ $M((x_1 + x_2)/2; (y_1+ y_2)/2)$

$M (\frac{- 1 - 5}{2}; \frac{3 + 9}{2})$ $M((-1-5)/2; (3+9)/2)$

$M (\frac{- 6}{2}; \frac{12}{2})$ $M((-6)/2; 12/2)$

= $M (- 3, 6)$ $M(-3, 6)$

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How do you find the midpoint of the line segment joining A(-1,3) and B(-5,9)?

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