How do you find the midpoint of the segment with the endpoints $(\frac{2}{3}, \frac{9}{2})$ $(2/3,9/2)$ and $(\frac{1}{3}, \frac{11}{2})$ $(1/3, 11/2)$ ?

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How do you find the midpoint of the segment with the endpoints $(\frac{2}{3}, \frac{9}{2})$ $(2/3,9/2)$ and $(\frac{1}{3}, \frac{11}{2})$ $(1/3, 11/2)$ ?

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Answer 1 · 2017-08-01T10:18:19

$(\frac{1}{2}, 5)$ $(1/2,5)$

Explanation:

$the coordinates of the midpoint are the average of the$ $"the coordinates of the midpoint are the average of the"$
$coordinates of the endpoints$ $"coordinates of the endpoints"$

$x_{midpoint} = \frac{1}{2} (\frac{2}{3} + \frac{1}{3}) = \frac{1}{2}$ $x_(color(red)"midpoint")=1/2(2/3+1/3)=1/2$

$y_{midpoint} = \frac{1}{2} (\frac{9}{2} + \frac{11}{2}) = 5$ $y_(color(red)"midpoint")=1/2(9/2+11/2)=5$

$\Rightarrow the midpoint = (\frac{1}{2}, 5)$ $rArr"the midpoint "=(1/2,5)$

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How do you find the midpoint of the segment with the endpoints $(\frac{2}{3}, \frac{9}{2})$ $(2/3,9/2)$ and $(\frac{1}{3}, \frac{11}{2})$ $(1/3, 11/2)$ ?

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How do you find the midpoint of the segment with the endpoints $(\frac{2}{3}, \frac{9}{2})$ $(2/3,9/2)$ and $(\frac{1}{3}, \frac{11}{2})$ $(1/3, 11/2)$ ?