Question

How do you find the minimum and maximum value of `y=3(x-3)^2-3`?

Answer 1

Minimum at `(3,-3)`

Explanation:

`y=a(x-h)^2+k` => Eqution of parabola in vertex form, where `(h, k)` is the vertex. For positive coefficient of squared term or a the parabola opens up, and if negative down. We have a minimum for upward and a maximum for down. So in this case:
`y=3(x-3)^2-3`
The parabola has a minimum value at vertex `(3, -3)`