Question

How do you find the polar coordinate for (32, -60)?

Answer 1

This point is in quadrant IV which puts is between 270 and 360 degrees.

Explanation:

First, find the reference angle in quadrant IV

reference angle `=arctan(60/32)=61.9^o`

`theta=270+61.9=331.9^o`

`r=sqrt(32^2+60^2)=68`

polar coordinate `=(68, 331.9^o)`

hope that helped