How do you find the product $14 t^{3} u (2 t^{2} u^{2} - 10 t u^{4} + 2)$ $14t^3u(2t^2u^2-10tu^4+2)$ ?

Question

1819 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-09T19:28:27

$= 28 t^{5} u^{3} - 140 t^{4} u^{5} + 28 t^{3} u$ $=28t^5u^3 -140t^4u^5 +28t^3u$

A product is the answer to a multiplication.
We need to use the distributive law and multiply the factor by each term inside the bracket.

$14 t^{3} u (2 t^{2} u^{2} - 10 t u^{4} + 2)$ $14t^3u(2t^2u^2 -10tu^4 +2)$

$= 28 t^{5} u^{3} - 140 t^{4} u^{5} + 28 t^{3} u$ $=28t^5u^3 -140t^4u^5 +28t^3u$

How do you find the product 14t3u(2t2u2−10tu4+2)14t^3u(2t^2u^2-10tu^4+2)?