How do you find the product of $3 p^{4} (4 p^{4} + 7 p^{3} + 4 p + 1)$ $3p^4(4p^4+7p^3+4p+1)$ ?

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How do you find the product of $3 p^{4} (4 p^{4} + 7 p^{3} + 4 p + 1)$ $3p^4(4p^4+7p^3+4p+1)$ ?

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Answer 1 · 2016-11-30T03:10:57

$12 p^{8} + 21 p^{7} + 12 p^{5} + 3 p^{4}$ $12p^8 + 21p^7 + 12p^5 + 3p^4$

Explanation:

Multiply $3 p^{4}$ $3p^4$ by each term in parenthesis:

$(3 p^{4} \cdot 4 p^{4}) + (3 p^{4} \cdot 7 p^{3}) + (3 p^{4} \cdot 4 p) + (3 p^{4} \cdot 1) \to$ $(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p) + (3p^4*1) ->$

$(3 p^{4} \cdot 4 p^{4}) + (3 p^{4} \cdot 7 p^{3}) + (3 p^{4} \cdot 4 p^{1}) + (3 p^{4} \cdot 1) \to$ $(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p^1) + (3p^4*1) ->$

Then multiply the numbers and the $x$ $x$ terms using the rules for exponents:

$12 p^{4 + 4} + 21 p^{4 + 3} + 12 p^{4 + 1} + 3 p^{4} \to$ $12p^(4+4) + 21p^(4+3) + 12p^(4+1) + 3p^4 ->$

$12 p^{8} + 21 p^{7} + 12 p^{5} + 3 p^{4}$ $12p^8 + 21p^7 + 12p^5 + 3p^4$

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How do you find the product of $3 p^{4} (4 p^{4} + 7 p^{3} + 4 p + 1)$ $3p^4(4p^4+7p^3+4p+1)$ ?

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Explanation:

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How do you find the product of 3p^4(4p^4+7p^3+4p+1)3p4(4p4+7p3+4p+1)3p^4(4p^4+7p^3+4p+1)?

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How do you find the product of $3 p^{4} (4 p^{4} + 7 p^{3} + 4 p + 1)$ $3p^4(4p^4+7p^3+4p+1)$ ?