How do you find the product of $(a-4)^2$ ?

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Answer 1 · 2018-04-12T01:11:00

See a solution process below:

Use this rule for this special case of quadratics:

$(color(red)(x) - color(blue)(y))(color(red)(x) - color(blue)(y)) = color(red)(x)^2 - 2color(red)(x)color(blue)(y) + color(blue)(y)^2$

Let:

$color(red)(a)$ replace $color(red)(x)$

$color(blue)(4)$ replace $color(blue)(y)$

$(color(red)(a) - color(blue)(4))^2 =>$

$(color(red)(a) - color(blue)(4))(color(red)(a) - color(blue)(4)) =>$

$color(red)(a)^2 - (2 * color(red)(a) * color(blue)(4)) + color(blue)(4)^2 =>$

$a^2 - 8a + 16$

How do you find the product of (a-4)^2(a-4)^2?