How do you find the real solutions of the polynomial 9x^3=5x^2+x?

1 Answer
Mar 17, 2018

x=0,x=5/18+-1/18sqrt61

Explanation:

"rearrange into standard form"

rArr9x^3-5x^2-x=0larrcolor(blue)"in standard form"

rArrx(9x^2-5x-1)=0

"equate each factor to zero and solve for x"

rArrx=0" or "9x^2-5x-1=0

"solve "9x^2-5x-1=0" using the "color(blue)"quadratic formula"

"with "a=9,b=-5" and "c=-1

x=(5+-sqrt(25+36))/18

color(white)(x)=(5+-sqrt61)/18

rArrx=5/18+-1/18sqrt61

rArrx=0,x=5/18+-1/18sqrt61larrcolor(blue)"real solutions"