How do you find the real solutions of the polynomial 9x^3=5x^2+x?
1 Answer
Mar 17, 2018
Explanation:
"rearrange into standard form"
rArr9x^3-5x^2-x=0larrcolor(blue)"in standard form"
rArrx(9x^2-5x-1)=0
"equate each factor to zero and solve for x"
rArrx=0" or "9x^2-5x-1=0
"solve "9x^2-5x-1=0" using the "color(blue)"quadratic formula"
"with "a=9,b=-5" and "c=-1
x=(5+-sqrt(25+36))/18
color(white)(x)=(5+-sqrt61)/18
rArrx=5/18+-1/18sqrt61
rArrx=0,x=5/18+-1/18sqrt61larrcolor(blue)"real solutions"