Question

How do you find the restricted values for `(x^2+x+15)/(x^2-3x)`?

Answer 1

See explanation

Explanation:

The restricted values for rational expressions are based on the fact that you cannot divide by zero, so you must restrict any value for any variable in the denominator of a rational expression that would make the value of the denominator be zero.

Hence

`x^2-3x=0=>x(x-3)=0=>x=0 or x=3`

Hence the restricted values are `0,3`