How do you find the roots of $12x=9x^2+4$ by factoring?

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Answer 1 · 2016-10-22T02:16:08

$x=2/3$

$12x=9x^2+4$

Subtract $12x$ from both sides.

$0=9x^2-12x+4$ or $9x^2-12x+4=0$

Factorise the equation.

$9x^2-6x-6x+4=0$

$3x(3x-2)-2(3x-2)=0$

$(3x-2)(3x-2)=0$

$3x-2=0$

$:.x=2/3$

How do you find the roots of 12x=9x^2+412x=9x^2+4 by factoring?