How do you find the roots of $x^{2} + 5 x - 14 = 0$ $x^2+5x-14=0$ ?

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Answer 1 · 2016-05-30T15:59:34

$x = - 7$ $x=-7$ or $x = 2$ $x=2$

Find a pair of factors of $14$ $14$ which differ by $5$ $5$ .

The pair $7, 2$ $7, 2$ works, so we find:

$0 = x^{2} + 5 x - 14 = (x + 7) (x - 2)$ $0 = x^2+5x-14 = (x+7)(x-2)$

Hence roots $x = - 7$ $x=-7$ and $x = 2$ $x=2$

How do you find the roots of x^2+5x-14=0x2+5x−14=0x^2+5x-14=0?