How do you find the second derivative of $ln(4x)$ ?

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Answer 1 · 2016-08-16T01:44:10

$f''(x) = -1/x^2$

$f(x) = ln(4x)$

$f'(x) = 1/(4x) * d/dx(4x)$ Standard differential and Chain rule)

$f'(x) =1/(4x) *4 = 1/x$

$f''(x) = -1/x^2$ (Power rule)

How do you find the second derivative of ln(4x) ln(4x) ?