How do you find the second derivative of $ln(x^2+5)$ ?

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Answer 1 · 2017-04-04T02:29:58

$(-2(x^2-5))/(x^2+5)^2$

Use natural logarithm derivative rules

$dy/dx =(2x)/(x^2+5)$

For second derivative use the quotient rule

$(d^2y)/(dx^2)= (-2(x^2-5))/(x^2+5)^2$

How do you find the second derivative of ln(x^2+5) ln(x^2+5) ?