How do you find the second derivative of $y=ln(x^2)$ ?

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Answer 1 · 2016-06-05T20:58:22

Deriving two times.

The first derivative is

$d/dxln(x^2)=(2x)/(x^2)=2/x$

then we derive again

$d/dx2/x=-2/x^2$ .

How do you find the second derivative of y=ln(x^2)y=ln(x^2) ?