How do you find the slope and intercept for $2x-3y=-12$ ?

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Answer 1 · 2017-05-25T11:44:51

Slope is $2/3$ , y-intercept at $(0,4)$ , x-intercept at $(-6,0)$

$2x -3y = -12 or 3y = 2x + 12 or y= 2/3 x +4$

Comparing with standard equation $y = mx + c$ we get

slope as $m=2/3$ , y-intercept as $c=4$ i.e at $(0,4)$

x-intercept can be found by putting $y=0$ in the equation as

$2x= -12 or x= -6$ i.e at $(-6,0)$
Slope is $2/3$ , y-intercept at $(0,4)$ , x-intercept at $(-6,0)$
graph{2x-3y = -12 [-10, 10, -5, 5]} [Ans]

How do you find the slope and intercept for 2x-3y=-122x-3y=-12?