How do you find the slope and intercept of #2x +3y = 12#?

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Answer 1 · 2018-03-21T02:45:27

slope #m=-2/3and Y# -intercept #=4#

If the equation of the line is #ax+by+c=0#,then

#slope : m=-a/band Y#-intercept #=-c/b.#

we have,

#2x+3y=12#

#=>2x+3y-12=0=>a=2,b=3,c=-12#

So, slope #m=-2/3and Y# -intercept #=-(-12)/3=12/3=

OR
#2x+3y=12=>3y=-2x+12=>y=(-2/3)x+12/3#
#y=(-2/3)x+4#

Comparing with #y=mx+c, #

where m is the slope and c is the y-intercept

we get #m=-2/3andc=4#