How do you find the slope and intercept of $2 x + 3 y = 12$ $2x +3y = 12$ ?

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How do you find the slope and intercept of $2 x + 3 y = 12$ $2x +3y = 12$ ?

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Answer 1 · 2018-03-21T02:45:27

slope $m = - \frac{2}{3} and Y$ $m=-2/3and Y$ -intercept $= 4$ $=4$

Explanation:

If the equation of the line is $a x + b y + c = 0$ $ax+by+c=0$ ,then

$s l o p e : m = - \frac{a}{b} and Y$ $slope : m=-a/band Y$ -intercept $= - \frac{c}{b} .$ $=-c/b.$

we have,

$2 x + 3 y = 12$ $2x+3y=12$

$\Rightarrow 2 x + 3 y - 12 = 0 \Rightarrow a = 2, b = 3, c = - 12$ $=>2x+3y-12=0=>a=2,b=3,c=-12$

So, slope $m = - \frac{2}{3} and Y$ $m=-2/3and Y$ -intercept #=-(-12)/3=12/3=

OR
$2 x + 3 y = 12 \Rightarrow 3 y = - 2 x + 12 \Rightarrow y = (- \frac{2}{3}) x + \frac{12}{3}$ $2x+3y=12=>3y=-2x+12=>y=(-2/3)x+12/3$
$y = (- \frac{2}{3}) x + 4$ $y=(-2/3)x+4$

Comparing with $y = m x + c,$ $y=mx+c,$

where m is the slope and c is the y-intercept

we get $m = - \frac{2}{3} and c = 4$ $m=-2/3andc=4$

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How do you find the slope and intercept of $2 x + 3 y = 12$ $2x +3y = 12$ ?

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Explanation:

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How do you find the slope and intercept of $2 x + 3 y = 12$ $2x +3y = 12$ ?