How do you find the slope and intercept of $2x +3y = 12$ ?

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Answer 1 · 2018-03-21T02:45:27

slope $m=-2/3and Y$ -intercept $=4$

If the equation of the line is $ax+by+c=0$ ,then

$slope : m=-a/band Y$ -intercept $=-c/b.$

we have,

$2x+3y=12$

$=>2x+3y-12=0=>a=2,b=3,c=-12$

So, slope $m=-2/3and Y$ -intercept #=-(-12)/3=12/3=

OR
$2x+3y=12=>3y=-2x+12=>y=(-2/3)x+12/3$
$y=(-2/3)x+4$

Comparing with $y=mx+c,$

where m is the slope and c is the y-intercept

we get $m=-2/3andc=4$

How do you find the slope and intercept of 2x +3y = 122x +3y = 12?