How do you find the slope and intercept of $3x+4y-16=0$ ?

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Answer 1 · 2016-01-21T23:16:16

I found: $m=-3/4$

You can try to write it in Slope-Intercept form:
$y=mx+c$
where $m$ will be the slope.

We isolate $y$ on one side:
$4y=-3x+16$
$y=-3/4x+4$
so that the slope will be $m=-3/4$

How do you find the slope and intercept of 3x+4y-16=03x+4y-16=0?