How do you find the slope and intercept of #-3x-8y+6=0#?

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Answer 1 · 2015-12-15T04:22:25

Slope-Intercept Form:
#y=mx+b#
Where #m# is the slope and #b# is the y-intercept.

Original Equation:
#-3x-8y+6=0#

To put an equation into slope-intercept form, you have to isolate #y#. This means you have to get #y# by itself:

#-3x-8y+6=0#

#-3x-8y=-6#

#-8y=3x-6#

#y=(3x-6)/(-8)#

#y=(-3/8)x+(3/4)#

Once you have #y# by itself, all you have to do is determine which number is your slope and which is your intercept.

You should end up with:
#m # (slope)# =(-3/8)#
and
#b# (y-intercept)# =(3/4)#