How do you find the slope and intercept of $3 y = 7$ $3y=7$ ?

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Answer 1 · 2018-07-17T23:23:38

$slope = m = 0$ $"slope" = m = 0$ ; $y$ $" "y$ -intercept $(0, \frac{7}{3})$ $(0, 7/3)$

Given: $3 y = 7$ $3y = 7$

The slope - intercept form of a line: $y = m x + b$ $y = mx + b$ ,

where $m$ $m$ = the slope and $b$ $b$ is the $y$ $y$ -intercept $(0, b)$ $(0, b)$

Put the given equation in slope - intercept form by dividing both sides of the equation by $3$ $3$ :

$\frac{3}{3} y = \frac{7}{3}$ $3/3 y = 7/3$

$y = \frac{7}{3} \Rightarrow y = 0 x + \frac{7}{3}$ $y = 7/3" " => " "y = 0x +7/3$

This is a horizontal line. They have slope $= 0$ $= 0$ .

This means $slope = m = 0$ $"slope" = m = 0$ ; $y$ $" "y$ -intercept $(0, \frac{7}{3})$ $(0, 7/3)$

How do you find the slope and intercept of 3y=73y=7?