How do you find the slope and intercept of $4x-1/3y=-2$ ?

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Answer 1 · 2016-01-26T10:40:20

$m=12$ and $b=6$ .

The equation of a line in slope-intercept form is $y=mx+b$ , where $m$ is the slope and $b$ is the y-intercept.

$4x-1/3y=-2$

To convert this equation to slope-intercept form, solve for $y$ .

Subtract $4x$ from both sides.

$-1/3y=-2-4x$

Simplify $-1/3y$ to $-y/3$

$-y/3=-2-4x$

Multiply both sides times $3$ .

$-y=-2(3)-4x(3)$

Simplify.

$-y=-6-12x$

Rearrange the right side.

$-y=-12x-6$

Multiply both sides times $-1$ .

$y=12x+6$

$m=12$ and $b=6$ .

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