How do you find the slope and intercept of 4x2y=12?

1 Answer
Jan 20, 2016

m=2
a=6
b=3

Explanation:

Given equation is 4x2y=12
Now, general slope equation is yyo=m(xxo) where m is the slope of the equation.
IF we rearrange the given equation, we see that it becomes
2y=4x12
Considering yo=0, and taking 4 common in the left hand side and dividing the whole equation by 2, we get what we want. That is
2y=4(x3) Divide by 2 and
y=2(x3).
Comparing the one we solved with the general equation, we see that m=2.

Now, for intercept form equation, the general equation is
ya=xb=1 where a is the y-intercept and b is the x-intercept.
So rearranging the original equation we had 4x2y=12 and dividing the equation by 12, we get
x3y6=1
So a=6 (since the y parameter has a negative value)
and b3