Question

How do you find the slope and intercept of `5y-4x+10=0`?

Answer 1

`"slope "=4/5," y-intercept "=-2`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`•color(white)(x)y=mx+b`

`"where m is the slope and b the y-intercept"`

`"rearrange "5y-4x+10=0" into this form"`

`"add 4x and subtract 10 from both sides"`

`rArr5y=4x-10`

`"divide all terms by 5"`

`rArry=4/5x-2larrcolor(blue)"in slope-intercept form"`

`"with slope "=4/5" and y-intercept "=-2`

Answer 2

See below:

Explanation:

The equation of the line is

`5y-4x=-10`

`5y=4x -10`

So

`y= (4x)/5 - 10/5`

`y=4/5x-2`

This is in the form of

`y=mx+c`

where;

• `y`-intercept `(c)=-2`
• slope `(m)=4/5`

Hope this will help you :)