#6y + 6 = 0#
First, make #y# by itself. Subtract #color(blue)6# from both sides:
#6y + 6 quadcolor(blue)(-quad6) = 0 quadcolor(blue)(-quad6)#
#6y = -6#
Divide both sides by #color(blue)6#:
#(6y)/color(blue)6 = (-6)/color(blue)6#
#y = -1#
When the equation is #y# equals to a number constant, that means it is a horizontal slope, or it has a slope of #0#.
There is no #x#-intercept since the equation never touches the #x#-axis. The #y#-intercept would be at #(0, -1)#, since whatever #x#-value you put into the equation does nothing. The equation is a constant, and it is always where #y = -1#.
Hope this helps!
