Question

How do you find the slope and intercept of `y= -2/5x + 20`?

Answer 1

`"slope "=-2/5," y-intercept "=20`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`•color(white)(x)y=mx+b`

`"where m is the slope and b the y-intercept"`

`y=-2/5x+20" is in this form"`

`"with slope "=-2/5" and y-intercept "=20`

Answer 2

Slope `= -2/5`

`y`-intercept `= 20`

Explanation:

The given equation is the standard slope-intercept form of a straight line equation,

`y = mx + c`

where

• `m =` slope `->` tangent of the angle made by the straight line intercepting one of the axes (`x` or `y`)
• `c =` the `y`-intercept, which remains constant.

Thus putting your equation in accordance with the standard equation, the slope is `-2/5` and the `y`-intercept is `20`.

graph{y = -2/5x + 20 [-80, 80, -40, 40]}

Since the slope is negative in magnitude, the tangent of the angle is greater than `180^@` and hence, the straight line cuts the positive `x` axis. Otherwise, in case of a positive slope, the straight line only cuts the positive `y` axis, thus giving us the intercept.

Here the straight line cuts the positive `y` axis at `(0,20)` and hence the `y`-intercept is `20`.