How do you find the slope and intercept to graph $2x - 6y = 12$ ?

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Answer 1 · 2016-03-22T18:16:04

the slope is $m = 1/3$

the y intercept is $b=-2$
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$2x - 6y =12$

isolate the term variable with $y$
$cancel(2x) -cancel(2x) - 6y =-2x +12$

$- 6y =-2x +12$

Isolate the $y$ variable
$((cancel(-6)y)/cancel(-6)) =(-2x +12)/(-6)$

$y =(-2x +12)/(-6)$

simplify the fraction

$y=1/3x-2$

the slope intercept equation is
$y=mx+b$
where
$m$ = the slope and $b$ = they intercept

$m = 1/3$

$b=-2$

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How do you find the slope and intercept to graph 2x - 6y = 122x - 6y = 12?